Question

SOMEONE PLEASE HELP ME ON MATH PROBLEMS PLEAASE IM IN ALG 2

Answer 1

wut qusion

Answer 2

Post them and we will try to help you.

Answer 3

find the annual percent increase or decrease that y=0.35(2.3)x models

Answer 4

0

Answer 5

what?

Answer 6

0 persent decrese or incerese

Answer 7

cool! i'm in algebra one but hey i'm only in 8th grade witch means i take online high school coarse that's pretty good right?

Answer 8

im confused???

Answer 9

i need help??

Answer 10

i tell u da answr u no listen not mi folt

Answer 11

thats not right

Answer 12

@Cheycheyy2 lets take this step by step okay :-).
This is a exponential growth type question, have you seen these before or are you just learning them and are completely confused? Are you stuck anywhere specific?

Answer 13

im horrible at math and im confused onthis whole section

Answer 14

Okay, don't worry about if you don't understand your whole section, lets just focus on the question at hand.

Exponential growth models this formula:\[\large x_t = x_0(1+r)^t\]

Notice your question:
\[\large y=0.35(2.3)^x\]

Do you see how your question relates to the original form?

Answer 15

yeah a little'

Answer 16

Awesome :D.
\[\large x_t = x_0(1+r)^t\]
\[\large x_t \implies y\]
\[\large x_0 \implies 0.35\]
\[\large (1 + r) \implies 2.3 \]

Notice the formula has a \((1+r)\).
Your question doesn't, this is because your equation is written in final form. (Meaning the 1 and r (rate) are added together.)

\[\large y=0.35(2.3)^x \implies \large y=0.35(2.3 - 1)^x \implies \large y=0.35(1.3)^x\]

So \(1.3\) is our initial rate, do you know how to turn a decimal into a percent?

Answer 17

no

Answer 18

oh yeah

Answer 19

its130%

Answer 20

Correct!
\[1.3 \times 100 = 130%\]

Answer 21

thanks can you help me on more

Answer 22

Sure, just post a new question :-).

Anyway if you want to know more about exponential growth and decay, you can check out:
http://www.regentsprep.org/regents/math/algebra/ae7/expdecayl.htm

Answer 23

write expression as a single logarthim