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What's the velocity of the object after the energy conversion from potential energy to kinetic energy after the object has been dropped from a height of 10 m?
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well what is the dicplacement and time?
Potential energy is given by the formula mgh where m is the mass of the object, g is the acceleration due to gravity assumed to be 10 m/s^2 and h is the height from where the object is released. The kinetic energy is given by the formula 12mv2 where m is the mass of the object and v is the velocity of the object in m/s. Assume that there is no wind drag and friction.
UrsBolt - You seem to have answered your own question... PE = mgh - you know all these KE = (mv^2)/2 KE = PE So the only unknown is v solve for v
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