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Mathematics 23 Online
OpenStudy (anonymous):

Need help ! attatchment below Here's a graph of a linear function. Write the equation that describes that function. express it in slope-intercept form.

OpenStudy (anonymous):

OpenStudy (anonymous):

@jigglypuff314

jigglypuff314 (jigglypuff314):

slope-intercept form: y = mx + b when m = slope and b = y-intercept

OpenStudy (jdoe0001):

pick 2 points from the graph notice the y-intercept comes handy and another one, notice 6,6 could be another

OpenStudy (anonymous):

ok so the intercept is the point where it hits the y axix which would be y=mx+4 how wouldi get the slop

jigglypuff314 (jigglypuff314):

slope = rise over run aka how much it goes up vs how much it goes to the right

OpenStudy (anonymous):

ok can you explain how i'd get that ?

jigglypuff314 (jigglypuff314):

mmm as jdoe0001 had said, there is a point (6, 6) and you know there's another point at (0, 4) \[slope = \frac{ rise }{ run } = \frac{ y _{2}-y _{1} }{ x _{2}-x _{1} } = \frac{ 6-4 }{ 6-0 } =\]

OpenStudy (anonymous):

so it'd be like 0.33

jigglypuff314 (jigglypuff314):

yep :) and as a fraction it would be 1/3 so m = 1/3

OpenStudy (anonymous):

y=1/3x+4?

jigglypuff314 (jigglypuff314):

yep! :D

OpenStudy (anonymous):

thanks (: Graph the equation below by plotting the y-intercept and a second point on the line. y=2/3x-4

OpenStudy (anonymous):

ok so y=mx+b m=2/3 y= -4

jigglypuff314 (jigglypuff314):

yep! so you would have a point at the y-intercept |dw:1391809717627:dw|

jigglypuff314 (jigglypuff314):

then a slope of 2/3 means that from a point you move up 2 and right 3 to get the next point

OpenStudy (anonymous):

never mind got it thanks bro

jigglypuff314 (jigglypuff314):

glad I could help :)

OpenStudy (anonymous):

hey if the slope is going left to right is it negative ? like so

jigglypuff314 (jigglypuff314):

yes, it would be negative :)

OpenStudy (anonymous):

ok so i got y= 6/1 - 5

OpenStudy (anonymous):

6/1x

jigglypuff314 (jigglypuff314):

mmm close :) " 5 " should be positive as the y-intercept is above the x axis and you might want to recheck your slope :)

OpenStudy (anonymous):

i thought sinceit was left to right the equation was subtraction ?

OpenStudy (anonymous):

and how do you do rise over run if it's negative , i just went to the left

jigglypuff314 (jigglypuff314):

subtraction like y = -x

jigglypuff314 (jigglypuff314):

mmm slope for this would be every time you go right one the line goes down 5 so slope = -5 so you get y = -5x + b

OpenStudy (anonymous):

ohh ok so y= -5x + 5 ?

jigglypuff314 (jigglypuff314):

yep :)

OpenStudy (anonymous):

thank you sir (:

jigglypuff314 (jigglypuff314):

you're welcome ;) (and I'm a girl, just saying XD )

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