Need help ! attatchment below Here's a graph of a linear function. Write the equation that describes that function. express it in slope-intercept form.
@jigglypuff314
slope-intercept form: y = mx + b when m = slope and b = y-intercept
pick 2 points from the graph notice the y-intercept comes handy and another one, notice 6,6 could be another
ok so the intercept is the point where it hits the y axix which would be y=mx+4 how wouldi get the slop
slope = rise over run aka how much it goes up vs how much it goes to the right
ok can you explain how i'd get that ?
mmm as jdoe0001 had said, there is a point (6, 6) and you know there's another point at (0, 4) \[slope = \frac{ rise }{ run } = \frac{ y _{2}-y _{1} }{ x _{2}-x _{1} } = \frac{ 6-4 }{ 6-0 } =\]
so it'd be like 0.33
yep :) and as a fraction it would be 1/3 so m = 1/3
y=1/3x+4?
yep! :D
thanks (: Graph the equation below by plotting the y-intercept and a second point on the line. y=2/3x-4
ok so y=mx+b m=2/3 y= -4
yep! so you would have a point at the y-intercept |dw:1391809717627:dw|
then a slope of 2/3 means that from a point you move up 2 and right 3 to get the next point
never mind got it thanks bro
glad I could help :)
hey if the slope is going left to right is it negative ? like so
yes, it would be negative :)
ok so i got y= 6/1 - 5
6/1x
mmm close :) " 5 " should be positive as the y-intercept is above the x axis and you might want to recheck your slope :)
i thought sinceit was left to right the equation was subtraction ?
and how do you do rise over run if it's negative , i just went to the left
subtraction like y = -x
mmm slope for this would be every time you go right one the line goes down 5 so slope = -5 so you get y = -5x + b
ohh ok so y= -5x + 5 ?
yep :)
thank you sir (:
you're welcome ;) (and I'm a girl, just saying XD )
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