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Write the equation of the line that is parallel to the line 3x - y = -3 and passes through the point (4, -2). y = -one thirdx - 6 y = -one thirdx - 14 y = 3x - 6 y = 3x - 14
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@bibby
get 3x - y = -3 into y = mx +b form. The slope of our line will be the same slope as that
please give me a sec.
y=3x+3
so what is the slope of the line we want?
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3
do now we're torn between c and d. I think we have to use the point slope formula to find out which
\[y-y_1=m(x-x_1)\] where y1 and x1 are the point (4,-2)
y-(-2)=3(x-4)
y+2=3(x-4) solve for y
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y=3x−14
yeah, good job
thanks do u mind helping me on 3 more questions if you can
I'll be away for 2ish minutes but tag me in your other questions
ok thanks
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