Gah...another pain that alludes me. So apparently, a crate of mass 60 kg is attached to one end of a string, and the other end of the string runs over a pulley and is held by a person as in the figure below. If the person pulls with a force of 77 N, what is the crate's acceleration? (Assume that upward is the positive direction. Indicate the direction with the sign of your answer.) Don't I just plug in the values into F=ma? Am I missing something else?
is there an angle?
No, no angle. just a mass being held up by a pull and the other end of the rope is being held or pulled down by a person.
52.14m/s^2
\[60 (9.8) -77\over 9.8\]
No that wasn't the right answer :( I appreciate you trying though.
I'd recommend uploading the figure
F = m a 77N = (60 kg) (a) a = 77/60 = 1.28 pulls down, so a is up.
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