Help please!!! Which of the following is a solution of x2 - 7x = -5? 7 plus or minus the square root of 69 divided by two 7 plus or minus the square root of 29 divided by two. negative 7 plus or minus the square root of 29 divided by two negative 7 plus or minus the square root of 69 divided by two.
do you know quadratic formula ?
Yes, b+/-sqrt(b^2-2ac)/2a
so, we have x^2 - 7x +5 = 0 can you find a,b,c ?
It's C, right?
i didn't work out yet, did you work it out ?
because, it would be -7+/-sqrt(-7^2-2(1)(-5))/2(1)
first of all, b = -7 so, -b = +7
so its not C or D
Riiighhht, I forgot about that part, damn. I think I have the formula wrong then.
Compare your quadratic equation with \(ax^2+bx+c=0\) find \[a=...?\\b=...?\\c=...?\\\] \[ \\ \sqrt{b^2-4ac}=...?\] then the two roots of x are: \(\huge{x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)
Okay, i've got it! It's 7+/-sqrt(29)/2 so the answer is B!
b = -7 a = 1 c = 5 b^2 - 4ac = 49 - 20 = 29 yes, you're correct :)
Can you help me with another one if possible(?)
sure
I already know it's not A. But, I don't know which one of the other 3 it could be. Solve x2 + 6x + 7 = 0. x = -1 and x = -5 3 plus or minus square root of 2 negative 3 plus or minus square root of 2 quantity of negative 3 plus or minus square root of 2 all over 2
what values of a,b,c you got ?
1, 6 and 7.
yes b^2 -4ac =....
6^2-4(1)(7) 36-28 8
good, so where are you stuck ?? proceed
[-6 +/- sqrt 8 ] /2 got this ?
Yeah. But then what, how does it end up like that?
-6/2 +/- (sqrt 8)/2 so you need to simplify sqrt 8 can you factor 8 ?
There's 4 and 2.
good! \(\sqrt 8 = \sqrt 4 \sqrt 2\) whats sqrt 4 ??
2
so it would go as 2sqrt(2)
yes
-6/2 +/- (sqrt 8)/2 =-6/2 +/- ( 2 sqrt 2)/2 simplify ?
(-3+/-(2sqrt2))/2 so iiiittsss D!
=-6/2 +/- ( 2 sqrt 2)/2 = -3 +/- sqrt 2 the '2' gets cancelled from numerator and denominator for BOTH the terms
doubts ?
So it just ends up just being C?
yes.
Thank you sooo much!!!
welcome ^_^
Join our real-time social learning platform and learn together with your friends!