fan and medal

A person leaves home at 8:00 a.m. and drives to a destination at a rate of 40 mph. The person returns at a rate of 25 mph and arrives at 2:30 p.m. How far was the destination?

65 miles

100 miles

130 miles

Question

fan and medal

A person leaves home at 8:00 a.m. and drives to a destination at a rate of 40 mph. The person returns at a rate of 25 mph and arrives at 2:30 p.m. How far was the destination?



65 miles

100 miles

130 miles

radar · Answer

The assumption is he immediately turned around at the destination???

anonymous · Answer

yes

jjuden · Answer

100 miles

anonymous · Answer

this is the only info they gave me

radar · Answer

surjithayer is providing the needed help.

jjuden · Answer

Total time 6.5 hr  (Assuming no stopping time)

D/r  = t

 D/40mph + D/25mph = 6.5

   65D = 6.5(40*25)

     D = 6.5(40*25)/65

     D = 100mi

anonymous · Answer

thanks jjuden but im goin to see what the other person says to ....no offense to you

anonymous · Answer

not saying your wrong either

anonymous · Answer

Let x be the distance between home and destination.


time taken to go from home to destination=x/40 hours
time taken to go back from destination to home x/25 hours
x/40+x/25=6.30hours=13/2 hours
solve for x

radar · Answer

Not complaining about the 100 mi answer.

anonymous · Answer

$$x \frac{5+8  }{ 200 }=\frac{ 13 }{ 2 },x=\frac{ 13 }{ 2}*\frac{ 200 }{ 13 }=100m$$

anonymous · Answer

https://media.glynlyon.com/g_alg01_2012/10/m90659.gif could i use this graph

j2lie · Answer

I think it is 65 miles because you add 25 mph and 40 mph.

radar · Answer

Don't understand the table .  time = 2.   I believe it is 6.5 hr.

j2lie · Answer

Do you add or multiply?