help me please go to my page for equation.

Question

anonymous · Answer

$$\sqrt{3x-11}=x-3$$

compassionate · Answer

What do you think the first step is? Hint: we need to get rid of that nasty radical.

anonymous · Answer

square root both sides by 2?

compassionate · Answer

You're onto something (:

Keep on going.

nurali · Answer

$$\sqrt{3x-11}=x-3$$

Squaring both sides

$$(\sqrt{3x-11})^2=(x-3)^2$$

$$3x-11=x^2-6x+9$$ 

$$x^2-6x-3x+9+11=0$$

$$x^2-9x+20=0$$

nurali · Answer

Factor the problem 
(x + 5)(x + 4) = 0 
Make each equal to 0 since if either is 0 then the product is 0 

x + 5 = 0 
subtract 5 from each side of the equation 
x = -5 

x + 4 = 0 
subtract 4 from each side of the equation 
x = -4

anonymous · Answer

thank you soooo much nurali :) and everyone else for helping :)

anonymous · Answer

what about this one. one second!
$$5\sqrt{\sqrt{x+7}}=25$$