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Algebra 7 Online
OpenStudy (anonymous):

help me please go to my page for equation.

OpenStudy (anonymous):

\[\sqrt{3x-11}=x-3\]

OpenStudy (compassionate):

What do you think the first step is? Hint: we need to get rid of that nasty radical.

OpenStudy (anonymous):

square root both sides by 2?

OpenStudy (compassionate):

You're onto something (: Keep on going.

OpenStudy (nurali):

\[\sqrt{3x-11}=x-3\] Squaring both sides \[(\sqrt{3x-11})^2=(x-3)^2\] \[3x-11=x^2-6x+9\] \[x^2-6x-3x+9+11=0\] \[x^2-9x+20=0\]

OpenStudy (nurali):

Factor the problem (x + 5)(x + 4) = 0 Make each equal to 0 since if either is 0 then the product is 0 x + 5 = 0 subtract 5 from each side of the equation x = -5 x + 4 = 0 subtract 4 from each side of the equation x = -4

OpenStudy (anonymous):

thank you soooo much nurali :) and everyone else for helping :)

OpenStudy (anonymous):

what about this one. one second! \[5\sqrt{\sqrt{x+7}}=25\]

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