Question

What is the equation of a line passing through (3, 4) and having a slope of -5?
A) y = 5x + 19
B) y = -5x + 11
C) y = -5x + 19
D) y = -1/5x + 19
E) y = -1/5x + 11

@nikato @jdoe0001 @Mertsj

Answer 1

y-y1=m(x-x1)

Answer 2

Do you know the point slope form? If you do, plug in the given info in it and solve for y

Answer 3

No I don't, what's the form? Lol.

Answer 4

Oh it's that^. And m=slope (x1,y1) are your points

Answer 5

\(\bf \begin{array}{lllll}
&x_1&y_1\\
&({\color{red}{ 3}}\quad ,&{\color{blue}{ 4}})\quad
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= -5
\\ \quad \\

y-{\color{blue}{ y_1}}={\color{green} m}(x-{\color{red}{ x_1}})\qquad \textit{plug in your values and solve for "y"}\)

Answer 6

y-4=-5*x-3 ? Is that right?

Answer 7

\(\bf y-{\color{blue}{ y_1}}={\color{green} m}(x-{\color{red}{ x_1}}) \) <---- point-slope form

Answer 8

the form is y-y1=m(x-x1)
m=slope=-5
y1=4
x1=3

Answer 9

y-4=-5* (x-3)

Answer 10

don't forget to distribute the -5

Answer 11

Ok

Answer 12

y=-5y + 19, right?

Answer 13

y=-5y + 19, right? \(\large \checkmark\)

Answer 14

Thanks :)