Question

the graph of a relation defined by 3y^2=x

Answer 1

have you done quadratics yet?

Answer 2

yes

Answer 3

ok... well, this one is just a parabola... and assuming you know the graph of a parabola... so, say \(\bf y= \pm x^2\) is a vertical parabola, going up
and \(\bf x=\pm y^2\) is a horizontal parabola, going sideways

what you have is a horizontal parabola... in this case..

\(\large 3y^2=x\implies 3(y-0)^2=(x-0)\\\qquad
\begin{array}{llll}
&&\textit{horizontal shrink}\\
&&\downarrow \\
(x-&0)=&3(y-&0)^2\\
center(&\uparrow, &&\uparrow )
\end{array} \)