Question

Perform the following operations and prove closure

x+4/x^2-5x+6 / x^2-16/x+3

Answer 1

Algebra 2 honors btw

Answer 2

when you divide fractions you invert the divisor and multiply
x^2 -16 should be recognized as the difference as two squares
factor to simplify
let me see what you have so far

Answer 3

(x +4)(x + 3)
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(x-3)(x-2)(x+4)(x-4)

Answer 4

thats where i am at now and am stuck please help

Answer 5

divide by x + 4

Answer 6

that just cancels both the x+4's right?

Answer 7

yes

Answer 8

now its x+3/(x-3)(x-2)(x-4)

Answer 9

that's what i have
don't know/remember how to prove closure sorry

Answer 10

x cannot be 2, 3 or 4 since you don't divide by zero

Answer 11

so that is the answer x is not equal to 2,3, or 4?

Answer 12

how do you prove closure?

Answer 13

what we have above
don't know/remember how to prove closure sorry

Answer 14

not sure