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Calculus1
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How would one factor the this: "(3x^2 - 5x + 2) = 0"? Any and all help is greatly appreciated! :)
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What did you try?
3*2 = 6 we awnt two numbers that multuply to 6 and add to -5, can you think of any?
(-3x + 1)(-x + 2) = 0 That's the best thing I've gotten so far...
so 3*2= 6, we want two numbers that multiply to 6, and add to -5 two such numbers are -3, -2 so 3x^2-5x+2 = 3x^2-3x-2x+2 = 3x(x-1)-2(x-1) = (x-1)(3x-2)
Okay... I get that. :)
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Sweet, yep this gets me the final answers I was racking my brain to figure out how to get. Thanks a million!
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