Question

anyone help with Input the equation of the given line in standard form. The line with m = -1/2 and the point (-2, -3).

Answer 1

the point slope form of equation of line is
\(\large y-y_1=m(x-x_1)\)
where m=slope =-1/2 here.
point =(x1,y1)= (-2,-3) --->x1= -2 ,y1= -3
just plug in values!

Answer 2

\[y-y _{1}=m(x-x _{1}). \]
Gradient, \[m=-\frac{ 1 }{ 2 }\]
point (-2,-3).
\[y-(-3)=(-\frac{ 1 }{ 2 })(x-(-3))\]
\[y+3=-\frac{ 1 }{ 2 }x-\frac{ 3 }{ 2 }\]
\[y=-\frac{ 1 }{ 2 }x-\frac{ 9 }{ 2 }\]