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Mathematics 13 Online
OpenStudy (anonymous):

BRAIN TEASER: You can place weights on both side of weighing balance and you need to measure all weights between 1 and 1000. For example if you have weights 1 and 3,now you can measure 1,3 and 4 like earlier case, and also you can measure 2,by placing 3 on one side and 1 on the side which contain the substance to be weighed. So question again is how many minimum weights and of what denominations you need to measure all weights from 1kg to 1000kg.

hartnn (hartnn):

1,2,4,8,16,32,64,128,256 and 512 count it.

OpenStudy (anonymous):

Anybody else have a different answer???

hartnn (hartnn):

did i miss any weight ? :P

OpenStudy (anonymous):

think so.

OpenStudy (anonymous):

last chance for anybody to take another guess.... than I am posting answer and doing another teaser!!!!!!

hartnn (hartnn):

i think thats it 10 different weights will give you every number from 1 to 100

OpenStudy (anonymous):

That is 1,3,9,27,81,243 and 729. not sure... :p

OpenStudy (anonymous):

That was asked to me some time ago... haha.

ganeshie8 (ganeshie8):

for that to work we may need a 3balance machine :)

hartnn (hartnn):

how about 5 liliegirl ??

ganeshie8 (ganeshie8):

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OpenStudy (anonymous):

going once....

OpenStudy (***[isuru]***):

u can measure a weight of 5 by putting the weight + 3+ 1 on one side and 9 on the other side..... :P

OpenStudy (anonymous):

going twice....

hartnn (hartnn):

lol, its this only 1,2,4,8,16,32,64,128,256 and 512

OpenStudy (anonymous):

Solution: For this answer is 3^0, 3^1, 3^2... That is 1,3,9,27,81,243 and 729.

hartnn (hartnn):

what!?

OpenStudy (***[isuru]***):

XD

OpenStudy (anonymous):

see?

hartnn (hartnn):

i am out xD thats enough internet for the day!

ganeshie8 (ganeshie8):

no see... in dire need of explanation :|

OpenStudy (anonymous):

@ganeshie8 All you need is to analyze the problem carefully. :))

ganeshie8 (ganeshie8):

ok looks im on my own... il try... thnks for replying though :)

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