Question

In an experiment, a ball is drawn from an urn containing 7 orange balls and 12 red balls. If the ball is orange, three coins are tossed. Otherwise two coins are tossed.
How many elements of the sample space will have a orange ball ?

Answer 1

8 possible "3-coin" combinations ---> 8*7 = 56

Answer 2

How did you get this?

Answer 3

Each time ball is orange (which occurs 7 of 19 possible times) 3 coins are tossed resulting in 8 possible cases

HHH
HHT
HTH
HTT
THH
THT
TTH
TTT

Answer 4

okay thanks and How many elements of the sample space are there altogether ?

Answer 5

Is it 56+8*12 = 56+96 = 152?

Answer 6

Please reply @dumbcow

Answer 7

no because only 2 coins are tossed when ball is red
how many combinations do you get when 2 coins are tossed?

Answer 8

4

Answer 9

So it is 56+12*4 = 56+48 right?

Answer 10

So 104 @dumbcow right?

Answer 11

yep :)