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Algebra 21 Online
OpenStudy (anonymous):

I need help prooving a trigometric equation

OpenStudy (science0229):

What is it?

OpenStudy (anonymous):

1/tanx=cotx/sin^2x+cos^2x

OpenStudy (cwrw238):

Hint ; sin^2x+cos^2x = 1

OpenStudy (anonymous):

my teacher wants me to provide proofs for the lhs and rhs and provide reasons but I am so clueless

OpenStudy (science0229):

First, you can write the left side as cosx/sinx since the reciprical of tanx, or 1/tanx, is cosx/sinx.

OpenStudy (anonymous):

so they both mean the same thing?

OpenStudy (science0229):

Yes.

OpenStudy (science0229):

And as @cwrw238 said, sin^2x+cos^2x=1, so the left side becomes cotx, which is cosx/sinx. Because the right side and left side are same, it is proven.

OpenStudy (anonymous):

okay thanks! that makes some sense, but im still confused as to what the reason are..

OpenStudy (science0229):

Let's start with the left side reasoning.

OpenStudy (science0229):

Do you understand that tanx=sinx/cosx?

OpenStudy (anonymous):

yes and that equals 1

OpenStudy (anonymous):

but its one over tanx

OpenStudy (science0229):

So, the reciprical of tanx is the reciprical of sinx/cosx, which is cosx/sinx. Right?

OpenStudy (anonymous):

ok right

OpenStudy (science0229):

Now, moving on to the right side.

OpenStudy (science0229):

Do you understand that sin^2x+cos^2x=1?

OpenStudy (anonymous):

yes

OpenStudy (science0229):

So, the denominator becomes 1.

OpenStudy (anonymous):

okay what about the numerator

OpenStudy (science0229):

The numerator is cotx,which can be written as cosx/sinx, right?

OpenStudy (anonymous):

right

OpenStudy (science0229):

Now, we just proved that left side is cosx/sinx, and same with the right side.

OpenStudy (anonymous):

okay thank you so much! I have so many other equations to proof though

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