Calculate the average speed of a complete round trip in which the outgoing 210km is covered at 98km/h , followed by a 1.0-h lunch break, and the return 210km is covered at 52km/h .
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OpenStudy (anonymous):
find the times for the moving legs from t=distance/velocity
add the lunch break to the two times and get
average velocity = total distance / total time
OpenStudy (anonymous):
67.96?
OpenStudy (anonymous):
should be 210/98 + 210/52 + 1 = total time
total distance = 2 x 210
I got 58 and a fraction
OpenStudy (anonymous):
m/h?
OpenStudy (anonymous):
58 km/h
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OpenStudy (anonymous):
No. km/hr
OpenStudy (anonymous):
Yes I got it thanks
OpenStudy (anonymous):
average velocity?
OpenStudy (anonymous):
average velocity = total distance/total time
usually called "average speed"
If they are trying to be tricky, using "velocity" rather than speed,
velocity being a vector displacement per time, in which case, they went nowhere net and the average velocity is 0.
OpenStudy (anonymous):
thanks
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