Question

The equation of line AB is (y−3) = 5 (x − 4). What is the slope of a line perpendicular to line AB?

Answer 1

The slope is the reciprocal of 5 which is -1/5

Answer 2

Solve the equation first, (y−3) = 5 (x − 4)

Apply distributive property to 5(x - 4)
(y−3) = 5 (x − 4)

(y−3) = 5x - 20

Now add both sides 3 to isolate y on the left side,

y-3 - 5x - 20
+3 +3

y = 5x -17

When the slope is perpendicular its the reciprocal , so you flip it and multiply it by -1

5 = 1/5 * -1 = -1/5

So y = -1/5x - 17

Answer 3

Thankyou for explaining

Answer 4

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