The equation of line AB is (y−3) = 5 (x − 4). What is the slope of a line perpendicular to line AB?

Question

anonymous · Answer

The slope is the reciprocal of 5 which is -1/5

the_fizicx99 · Answer

Solve the equation first, (y−3) = 5 (x − 4)

Apply distributive property to 5(x - 4)
(y−3) = 5 (x − 4)

(y−3) = 5x - 20

Now add both sides 3 to isolate y on the left side,

y-3 - 5x - 20
 +3         +3

y = 5x -17

When the slope is perpendicular its the reciprocal , so you flip it and multiply it by -1

5 = 1/5 * -1 = -1/5

So y = -1/5x - 17

anonymous · Answer

Thankyou for explaining

the_fizicx99 · Answer

yw