How do you write 4 log m-log n into a single logarithm?

Question

mathmale · Answer

Would you mind typing out the three rules of logs that apply to this kind of problem?  Hint:  log m + log n = log mn.  (Can you put that into words?)

anonymous · Answer

remember these rules
$$\log x - \log y = \log(\frac{ x }{ y })$$
$$x \log y = \log y^{x}$$

jdoe0001 · Answer

http://www.chilimath.com/algebra/advanced/log/images/rules%20of%20exponents.gif use rule 1

mathmale · Answer

Chris:  In your shoes I'd take careful notes on this material for later reference.

Which of the 3 rules applies to the expression 4 log m?  Please explain your reasoning and rewrite 4 log m as appropriate.