Question

How do you write 4 log m-log n into a single logarithm?

Answer 1

Would you mind typing out the three rules of logs that apply to this kind of problem? Hint: log m + log n = log mn. (Can you put that into words?)

Answer 2

remember these rules
\[\log x - \log y = \log(\frac{ x }{ y })\]
\[x \log y = \log y^{x}\]

Answer 3

http://www.chilimath.com/algebra/advanced/log/images/rules%20of%20exponents.gif use rule 1

Answer 4

Chris: In your shoes I'd take careful notes on this material for later reference.

Which of the 3 rules applies to the expression 4 log m? Please explain your reasoning and rewrite 4 log m as appropriate.