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Mathematics 10 Online
OpenStudy (j2lie):

How to factor 18a^2+15a-18?

OpenStudy (j2lie):

@whpalmer4 can you help me?

OpenStudy (whpalmer4):

first, do you see any common factors in the coefficients?

OpenStudy (j2lie):

yes 3.

OpenStudy (whpalmer4):

okay, generally it makes life easier to factor out any common factors first, so the numbers we work with are as small as possible

OpenStudy (whpalmer4):

so that gives us \[3(6a^2+5a-6)\]right?

OpenStudy (j2lie):

yes

OpenStudy (whpalmer4):

do you remember the procedure for splitting the middle when the leading term has a coefficient other than 1?

OpenStudy (whpalmer4):

we'll just leave the 3 behind for the moment and factor \[6a^2+5a-6\]

OpenStudy (j2lie):

6a^2+6a-1a_6

OpenStudy (whpalmer4):

huh?

OpenStudy (whpalmer4):

so the procedure is to multiply the first and last term's coefficients: 6*-6 = -36 Now we look for a pair of factors of -36 that sum to +5

OpenStudy (j2lie):

you have to split the middle coefficient.

OpenStudy (j2lie):

this is my answer #(2a+3)(3a-2)

OpenStudy (j2lie):

3*

OpenStudy (whpalmer4):

that's correct!

OpenStudy (anonymous):

3(2x+3)(3x−2)

OpenStudy (j2lie):

yay my dad said I'm wrong.

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