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Please solve step by step http://awesomescreenshot.com/0472bvq209
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\[4^{-3.5}=(2^2)^{-3.5}=2^{2\times(-3.5)}=2^{-7}=\frac{ 1 }{ 2^7 }=\frac{ 1 }{ 128 }\]
Thank you very much
You're welcome.
\(A^{-m}=1/A^{m}\) Okay
Is that the formula
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Yup it's a formula, but it is not the one you need right now i guess
What's the one I need o.o
I thought you understand what @gunsodo just do ?
It makes sense what he did... yes. Lol nvm
The easiest way to solve problems like this, is to make the exponent be an integer.
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Yup excellent :)
Thanks.
Does that involve squaring the whole number?
Nope, I don't think that you need the square here
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