Question

2t^3=5t-11t^2

Answer 1

First I took everything over to one side, so.. 2t^3-5t+11t^2

then set it to zero 2t^3-5t+11t^2=0


then didivded by t..so t(2t^2-5+11t)

Then I tried multiplying 11 by 2 which =22

but 22 and 5 dont factor.

Answer 2

I tried quadratic formula but I got 5+- (sq root) -63/4

Answer 3

2t^3 + 11t^2 - 5t = 0
t(2t^2 + 11t - 5) = 0
2t^2 + 11t- 5 = 0

using the quadratic formula ..
\[t = \frac{ -11 \pm \sqrt{161} }{ 4 }\]

Answer 4

Right.. so then that'd be my final answer?

Answer 5

yeah.

Answer 6

Thanks.