Question

Bruno will spin the arrow on the spinner 3 times.


What is the probability that the arrow will stop on A, then B, then C?
The spinner is labeled A through E

Answer 1

The probabilities for each area are each equally likely:
$$
P(A)=P(B)=P(C)=P(D)=P(E)=\cfrac{1}{5}
$$
Note that \(\Large \Sigma_{i\in \text{(A-E)}}P(i)=1\)

Each stop is independent of the other. So the probability of stopping on A then B then C is:
$$
P(A)\times P(B)\times P(C)=\cfrac{1}{5}\times\cfrac{1}{5}\times\cfrac{1}{5}\\
=\cfrac{1}{5^3}\\
$$

Answer 2

thank you very much!