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Find the derivative of \[g(x)= 2x^2-3\] by using the difference quotient. g ' (x) =_________
Try it. Use the power rule on the 2x^2, and the derivative of a constant (like -3) is zero.
okay... so power rule= Knk(n-1) right? Or did i miss something :/
so 2x^2 = 2* 2x^2-2 ?
^why are you subtracting 2?
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oh oops i meant 1 2* 2x^2-1 is that better?
Yes
okay so 2*2x = 4x ? is that the answer? :O
Yep
ah yay! thank you!!
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