Question

Solve using substitution.

y = -x
y = x^3 + 3x^2 + 3x

Answer 1

\(\bf {\color{red}{ y}} = -x\\
{\color{red}{ y}} = x^3 + 3x^2 + 3x\\ \quad \\ \quad \\
-x=x^3 + 3x^2 + 3x\implies 0=x^3 + 3x^2 + 3x+x\\ \quad \\
0=x^3 + 3x^2+4x\implies 0=x(x^2+3x+4)\)

factor the quadratic, solve for "x"

Answer 2

Thank you so much

Answer 3

yw