px + qy = r
2px - qy = 2r
When solving this system of equations, x =

Question

px + qy = r
2px - qy = 2r
When solving this system of equations, x =

anonymous · Answer

Input in standard form the equation of the given line.

The line with m = 1/2 and b = 3.

noorik. · Answer

try to sum the two equations
(px+qy) + (2px-qy) = r + 2r
then 3px = 3r
px = r

anonymous · Answer

That can't be right because my options are 
p/r
r/p
3r/2p

noorik. · Answer

no it's correct, because
px=r then x = r/p

anonymous · Answer

Okay! Could you help with this one?
Input in standard form the equation of the given line.

The line that passes through (-1, -3) and (2, 1)

noorik. · Answer

try to find the slope between the two points, and it's a linear equation of the first degree

anonymous · Answer

I have no clue what any of that means.

noorik. · Answer

ok
the slope law is
$$slope (m) = \frac{ y2-y1 }{ x2-x1 }$$

anonymous · Answer

Okay?

noorik. · Answer

$$m = \frac{ 1-(-3) }{ 2-(-1) } = \frac{ 4 }{ 3 }$$

anonymous · Answer

Last one.. can you help me with this?

Input in standard form the equation of the given line.

The line with m = 1/2 and b = 3.

noorik. · Answer

then to find the equation of the line
$$\frac{ 4 }{ 3 } = \frac{ y-1 }{ x-2 }$$
then 4x-8 = 3y-3
3y = 4x -5

noorik. · Answer

the last question
y = x/2 +3