please help me with this !!
find the range of (x^2+3x+10)/(x^2+6x+5)
Ans: (-infinity, -3/4-sqrt(5/2)] U [-3/4+sqrt(5/2),infinity)

Question

please help me with this !!
find the range of (x^2+3x+10)/(x^2+6x+5) 
Ans: (-infinity, -3/4-sqrt(5/2)] U [-3/4+sqrt(5/2),infinity)

anonymous · Answer

$$y= \frac{x^2+3x+10}{x^2+6x+5}$$

anonymous · Answer

this is going to be a real pain
i think you have to solve this for $x$ and see what you get in terms of $y$

campbell_st · Answer

well you can factor the numerator and denominator... 

then look at the restictions in the domain... then see whats happening to the range close to those values.

anonymous · Answer

@satellite73 i did solve but not getting the right answer !!

anonymous · Answer

This isn't your typical well known functions like y = x^2, or y = sin(x), etc, that we can easily find the range with little to no calculation. So your only best bet is to rely on technology

anonymous · Answer

Type that function in wolfram alpha and you'l have the  answer.

anonymous · Answer

@sourwing but i need to work it out !! ..Tried wolfram long back

campbell_st · Answer

why not just graph it... and see whats happening...

anonymous · Answer

You'll need  calculus to find the range, which requires you to find increasing/decreasing, concave up/concave down, vertical/horizontal asymptotes, etc,.. You'll probably have to spend like an hour if you do it by hand.

campbell_st · Answer

here's the graph

anonymous · Answer

see what i mean? technology will give you answer right away.

btw, horizontal asymptote is y = 1 
:DD