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Mathematics 15 Online
OpenStudy (anonymous):

Help! Please? I will reward you!

OpenStudy (anonymous):

Here it is

OpenStudy (anonymous):

If you could gimmie the answers and a explanation that would be cool.

OpenStudy (anonymous):

1.

OpenStudy (anonymous):

1a, 2c, 3 is also a, 4b Try using cross products, then solving the resulting equation. Cross products is when you have an equation that says a/b = c/d, you can turn that into ad = bc.\[\frac{ a }{ b } = \frac{ c }{ d } \]\[ad = bc\]

OpenStudy (anonymous):

okay I understand this kind of stuff now. thank you both

OpenStudy (anonymous):

You're welcome.

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