Question

The equation is F(d)=0.0303d+1.
How deep must you dive for water pressure to be twice the pressure at sea level? and find the water pressure at 1943 feet?

Answer 1

Pressure at sea level = F(0). To find the depth at which the pressure is twice the pressure at sea level, solve \[2*F(0) = 0.0303d+1\]for \(d\). To find the pressure at 1943 feet, evaluate F(1943). The unit for the value produced by F(d) is bars. Every 33 feet you go gets you another atmosphere's worth of pressure.