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determine the constant k so that the graph of 2(y+3y)=3k(x-1) will have the slope of 6
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write in y=mx+b form
2*4y=3k(x-1) how can u write this as y=something
nvvm
\[ 2(y+3y)=3k(x-1) \]Same as \[ 8y=3k(x-1) \]Differentiate both sides \[ 8y' = 3k \]We want \(y'=6\).\[ 8(6) = 3k \]Solve for \(k\). I think.
I didn't even know you can do it that way @wio good to know and thank you
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