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Write an equation of the line below.
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I assume you mean the equation OF the line below. The equation for a straight line has the general form y=mx+c m is the gradient of the line c is the offset and is given by the value of Y where the line crosses the Y axis The gradient is given by (change in y)/change in x You can see that the line passes exactly through (2,5) and (0,-1) so you can work out the gradient from those 2 points (be careful about the minus signs) you can also get the value where the line crosses the Y axis So write the formula y=mx+c using the values you got from above...
hey @MrNood somebody already helped me with this but could you help me with something else
try me...
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