Question

solve by factoring the following quadratic
4x^2-x^2-4x+1

Answer 1

To solve (find the roots of) the quadratic equation =0:
First, we'll attempt to factor this quadratic equation as a trinomial.

4x^2-x^2-4x+1which is equal to 3x^2-4x+1 is a valid trinomial that might be factorable.
This trinomial can be factored. Here is it in factored form:
3x^2-4x+1= ( x-1 )( 3x-1 )
With the two factors found, we now solve the equations:
x-1 =0 and 3x-1 =0.

Solving x-1 =0, we get that x= 1

Solving 3x-1 =0 and, we get that x=1/3

Therefore, x= 1 and x=1/3 are the roots to the quadratic equation 3x^2-4x+1