Question

Intergrate please!

Answer 1

\[\int\limits_{0}^{\pi/6}\sin2x\]

Answer 2

What is stopping you?

Answer 3

Do you need help finding the anti derivative?

Answer 4

Consider the function \(a\cos(bx)\). We can use chain rule to differentiate. \[
[a\cos(bx)]' = -ab\sin(bx)
\]If we want \(b=2\) and \(-ab=1\), this means \(a=-1/2\) then we can see \[
\left[-\frac 12\cos(2x)\right]'=\sin(2x)
\]

Answer 5

There are easier ways to do it, but I'm assuming you don't know those techniques and wanted you to consider this undetermined coefficients method.