Are the following points on the graph of f(x)=3x^2 + 7x -8 (-3,-2) (-1, -10) (1,2) (3, 45)
for the first point (-1,-10) if you replace x by -1 and get -10 the point is on the graph
it's not the first point, but anyway..
how can you test and see if the points are on the line
f(-1) = 3(-1)^2+7(-1)-8 f(-1) = 3-7-8 f(-1) = -12 the point (-1,-10) is not on the graph
let's say you have the point (a,b) you know the point is on the line if f(a)=b
the values must satisfy the equation
even if they are points...ex. (5, -2)
any point, you substitute x and calculate y, if they match then the point is on the line
try the point (-3,-2) what is f(-3)?
if plugged into the equation i originally provided ( f(x) = 3x^2 +7x -8... then it would be -2
ohhhh
this means the point (-3,-2) is on the line of this function
THANK YOU SO MUCH! you really helped me put that into perspective without completely giving me the answer! thank you!
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