Question

Trig
Having some major trouble with these problems:

1. The angles that satisfy this expression cos^-1(-3/2) are:
a. 5pi/6+2pi(n)
b. 5pi/6
c. 5pi/6; 7pi/6
d. 5pi/6+2pi(n); 7pi/6+2pi(n)
I know one of them is 5pi/6.

2. Find all the angles that fit the expression: tan^-1(sqrt3/3)
a. 2pi(n); 7pi/6+2pi(n)
b. pi/6+2pi(n); 7pi/6
c. pi/6+2pi(n); 7pi/6+2pi(n)
d. 2pi(n); 7pi/6

3. Find all the angle values that fit the trigonometric expression tan^-1 0.
a. pi+2pi(n)
b. pi(n);pi+2pi(n)
c. 2pi(n); pi+2pi(n)
d. 2pi(n)

Thank you so much!

Answer 1

I think number 1 is C? 5pi/6; 7pi/6

Answer 2

to be invertible the function can have two distinct arguments with same image?

Answer 3

Uh I have no idea? I have not learned that.

Answer 4

http://en.wikipedia.org/wiki/Inverse_trigonometric_functions

Answer 5

this question is kind of wrong, you only should have one ans.

Answer 6

if i take the inverse there, in my draw,{ will have two images, then its not a function

Answer 7

and the first cos(x)=-1.5, this is not even real

Answer 8

-1<=cos(x)<=1

Answer 9

I guess that's why I'm having so much trouble with them.

Answer 10

try it in your calculator acos(-3/2)