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Velocity help:
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If a ball is thrown into the air with a velocity of 49 ft/s, its height (in feet) after t seconds is given by \[y = 49t - 16t^2\]. Find the velocity when t = 2.
Just curious but how does one obtain the ambassador badge?
Like be an ambassador from another math site or what? :/
Not the place to ask that, there is an ambassador section.
I am trying to remember back to this sort of question lol, gimme a sec luilui.
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You need to take the derivative with respect to time.
dy/dt gives velocity where y is the displacement Just evaluate it and put t=2.
Yerp, \(\large{v=\frac{dy}{dt}}\) And just like Aravind said, when you have done this, you just plug in your given value and voila :D
Alright, thanks guys :)
Nu problemo brubru.
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