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using factoring and the zero product property to find the zeros of each quadratic function. f(x)=4x^2+4x-24
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factor out 4 \[f(x) = 4(x^2 +x - 6)\] now factor the quadratic.... hope it helps
i got that far, but like i dont really know what to do afterwards.
ok... so what are the factors of -6 that add to 1 the larger factor is positive... and the smaller negative so f(x) =4(x + factor1)(x + factor 2)
so then, f(x)=4(x+3)(x-2)?
yep... now to find the zeros solve x + 3 = 0 x -2 = 0
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oooh okay thnak yooou ^_^
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