Graph the equation. Be sure to simplify the equation into standard form Ax+By=C before graphing it.
3x+4y-3=-15
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OpenStudy (vshiroky):
This one I am unsure of how to do..
jimthompson5910 (jim_thompson5910):
First add 3 to both sides
3x+4y-3=-15
3x+4y-3+3=-15+3
3x+4y = -12
Now the equation is in Ax+By = C form
jimthompson5910 (jim_thompson5910):
One way to graph this is to find the x and y intercepts
To find the x-intercept, plug in y = 0 and solve for x
3x+4y = -12
3x+4(0) = -12
3x+0 = -12
3x = -12
x = -12/3
x = -4
So the x-intercept is the point (-4,0)
jimthompson5910 (jim_thompson5910):
The y-intercept is found the same way, but plugging in x = 0 and solving for y this time
3x+4y = -12
3(0)+4y = -12
0+4y = -12
4y = -12
y = -12/4
y = -3
telling us that the point (0,-3) is also on this line and this point is the y-intercept
OpenStudy (vshiroky):
Ok... Would the second one be (0,-3)?
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jimthompson5910 (jim_thompson5910):
now plot the two points (-4,0) and (0,-3) and draw a straight line through them
jimthompson5910 (jim_thompson5910):
that is correct
OpenStudy (vshiroky):
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jimthompson5910 (jim_thompson5910):
That looks good to me
OpenStudy (vshiroky):
Yay!! Thank you yet again haha.
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