Mathematics
10 Online
OpenStudy (anonymous):
what is the cot 90
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jimthompson5910 (jim_thompson5910):
cot(x) = cos(x)/sin(x)
cot(90) = cos(90)/sin(90)
cot(90) = 0/1
cot(90) = 0
This is assuming they want it in degree mode.
OpenStudy (anonymous):
Its wants the exact value
jimthompson5910 (jim_thompson5910):
0 is the exact value
OpenStudy (anonymous):
thank you
jimthompson5910 (jim_thompson5910):
you're welcome
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OpenStudy (anonymous):
then what is the exact value -300
jimthompson5910 (jim_thompson5910):
hint: -300 is coterminal to 60
jimthompson5910 (jim_thompson5910):
so cot(-300) = cot(60)
OpenStudy (anonymous):
so it is 60
jimthompson5910 (jim_thompson5910):
no
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jimthompson5910 (jim_thompson5910):
you have to evaluate cot(60) to get the answer
OpenStudy (anonymous):
do you divide the sin and the cos
jimthompson5910 (jim_thompson5910):
it's actually
cot(60) = cos(60)/sin(60)
jimthompson5910 (jim_thompson5910):
use a unit circle to find cos(60) and sin(60)
then simplify
OpenStudy (anonymous):
I got 3.124
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jimthompson5910 (jim_thompson5910):
keep the answer in exact radical form
jimthompson5910 (jim_thompson5910):
For example, you should have gotten that
cos(60) = 1/2
sin(60) = sqrt(3)/2
OpenStudy (anonymous):
oh okay now I get it
OpenStudy (anonymous):
thanks
jimthompson5910 (jim_thompson5910):
tell me what you get
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OpenStudy (anonymous):
0.17
jimthompson5910 (jim_thompson5910):
you should get a square root in your answer
OpenStudy (anonymous):
how do you do that do you square the answer
jimthompson5910 (jim_thompson5910):
cos(60)/sin(60) = (1/2)/(sqrt(3)/2)
cos(60)/sin(60) = (1/2)*(2/sqrt(3))
cos(60)/sin(60) = 1/sqrt(3)
cos(60)/sin(60) = sqrt(3)/3
jimthompson5910 (jim_thompson5910):
So that shows us that \[\Large \cot(-300^{\circ}) = \frac{\sqrt{3}}{3}\]
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OpenStudy (anonymous):
I suck at this
jimthompson5910 (jim_thompson5910):
keep practicing and you'll get better at it
OpenStudy (anonymous):
maybe I will