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Mathematics 10 Online
OpenStudy (anonymous):

what is the cot 90

jimthompson5910 (jim_thompson5910):

cot(x) = cos(x)/sin(x) cot(90) = cos(90)/sin(90) cot(90) = 0/1 cot(90) = 0 This is assuming they want it in degree mode.

OpenStudy (anonymous):

Its wants the exact value

jimthompson5910 (jim_thompson5910):

0 is the exact value

OpenStudy (anonymous):

thank you

jimthompson5910 (jim_thompson5910):

you're welcome

OpenStudy (anonymous):

then what is the exact value -300

jimthompson5910 (jim_thompson5910):

hint: -300 is coterminal to 60

jimthompson5910 (jim_thompson5910):

so cot(-300) = cot(60)

OpenStudy (anonymous):

so it is 60

jimthompson5910 (jim_thompson5910):

no

jimthompson5910 (jim_thompson5910):

you have to evaluate cot(60) to get the answer

OpenStudy (anonymous):

do you divide the sin and the cos

jimthompson5910 (jim_thompson5910):

it's actually cot(60) = cos(60)/sin(60)

jimthompson5910 (jim_thompson5910):

use a unit circle to find cos(60) and sin(60) then simplify

OpenStudy (anonymous):

I got 3.124

jimthompson5910 (jim_thompson5910):

keep the answer in exact radical form

jimthompson5910 (jim_thompson5910):

For example, you should have gotten that cos(60) = 1/2 sin(60) = sqrt(3)/2

OpenStudy (anonymous):

oh okay now I get it

OpenStudy (anonymous):

thanks

jimthompson5910 (jim_thompson5910):

tell me what you get

OpenStudy (anonymous):

0.17

jimthompson5910 (jim_thompson5910):

you should get a square root in your answer

OpenStudy (anonymous):

how do you do that do you square the answer

jimthompson5910 (jim_thompson5910):

cos(60)/sin(60) = (1/2)/(sqrt(3)/2) cos(60)/sin(60) = (1/2)*(2/sqrt(3)) cos(60)/sin(60) = 1/sqrt(3) cos(60)/sin(60) = sqrt(3)/3

jimthompson5910 (jim_thompson5910):

So that shows us that \[\Large \cot(-300^{\circ}) = \frac{\sqrt{3}}{3}\]

OpenStudy (anonymous):

I suck at this

jimthompson5910 (jim_thompson5910):

keep practicing and you'll get better at it

OpenStudy (anonymous):

maybe I will

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