write an equation of the line containing the given point and perpendicular to the given line.
(0,5);9x+2y=3
the equation of the line is y= ?
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OpenStudy (anonymous):
@jigglypuff314
jigglypuff314 (jigglypuff314):
first find the slope of 9x+2y=3
what do you get?
OpenStudy (anonymous):
-9/2
jigglypuff314 (jigglypuff314):
yep :)
then the slope of a line perpendicular to that is
the flipped opposite
so the flipped opposite would be 2/9
so you need to make an equation of a line
that has slope= 2/9 and point (0, 5)
OpenStudy (anonymous):
so how would I do that?
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jigglypuff314 (jigglypuff314):
slope-intercept form: y = mx + b
when m = slope and b = y-intercept
so since slope = m = 2/9
you get y = (2/9)x + b
then temporarily plug in point (0, 5)
to find " b "
so 5 = (2/9)(0) + b solve for b
OpenStudy (anonymous):
5
jigglypuff314 (jigglypuff314):
yup :)
so plug back into y = (2/9)x + b
so y = (2/9)x + 5
OpenStudy (anonymous):
so do I put the parenthesis?
jigglypuff314 (jigglypuff314):
yeah, it's best if you do
since it could be misinterpreted as 2/(9x) otherwise...