y=-5 What is the slope and y intercept? slope:0? y intercept (0,-5) Is that right? I'm not sure if you can have a slope of 0
slope:0? y intercept (0,-5) \(\Large \checkmark\) |dw:1392245189549:dw|
You can have a slope of zero :P
\(\bf slope = {\color{green}{ m}}= \cfrac{rise}{run}\) notice is a horizontal line, no matter what \(y_1\ and \ y_2\) you pick, they'll both be -5 -5 -(-5) = 0 so the fraction numerator will always be 0, thus the slope as well
Thank you :)
If I have (2,11) and (3,7) My slope would be -4 right?
yeap
Yay
I have another question lol
Use the slope intercept form to graph the equation y=-8x
I know the slope is -8. Would the y intercept be (0,0)
Yes...when there is no stated y-intercept, it begins at the origin
|dw:1392245072832:dw|
would that be my graph?
That looks correct to me!
So if it's a negative slope I go down and to the right?
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If you divide a negative and negative is it positive? I appreciate all the help
For instance I have 5x-6y=1 Then it'd be y=-5/6x+1?
5x - 6y = 1 -5x -5x -6y = -5x + 1 ------------- -6 -6 -6 y = (5/6)x - (1/6)
Sometimes I forget to do the last number divided by the 6 lol thank you
Yeah you have to divide everything by the -6 :)
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