Question

Any idea how to solve this?
question below

Answer 1

This is a bit tougher than your average missile test question.

y coordinate will be y = vo sin@ t +(1/2)(-9.88m/s^2) t^2

x coordinate will be x = vo cos@ t

Your ramp is at y=0 up to x=50, then y = (x-50)sin(42) for x>50.

You might just graph it, putting that ramp on the graph, too.

Answer 2

why (x-50) ?

Answer 3

@douglaswinslowcooper

Answer 4

The ramping up does not start until x=50.

Answer 5

yes, it is
but why it is not (x+50) ?

i still dont get it:/
sorry

Answer 6

Yes. It is (x-50), but I think is tan42º instead of sin42º. Because x is the coordinate where the missile hit the ramp, . Look at the ramp: there is a right triangle there where the adjacent side is (x-50) and opposite side is y, so you should use tan 42º to get y.

Answer 7

can you draw it again for me?
it's hard to visualize , i'm confused
is it like this?