Question

Write a polynomial in standard form with given zeros at -1,-1,and -6

Answer 1

x-(-1)=? when x=-1?

Answer 2

Its just when x=-1
but it would be (x+10=0 right?

Answer 3

(x+1)=0

Answer 4

using the zero factor property that means:\[(x+1)(x+1)(x+6)=0\]
because at leat one of them must equal zero for the whole thing to equal 0
because x+1=0 (solution is -1)
x+6=0 (solution is -6)

Answer 5

can u multiply that out yourself?

Answer 6

(x+1)(x+1)=x^2+2x+1

Answer 7

so its actually \[(x^2+2x+1)(x+6)\]

Answer 8

so the polynomial is \[x^3+8x^2+13x+6\]

Answer 9

or it could also just be:
\[x^2+7x+6\] because (x+1)(x+6)=0