Question

**Picture in comments** The figure below shows a triangle with vertices A and B on a circle and vertex C outside it. Side AC is tangent to the circle. Side BC is a secant intersecting the circle at point X. What is the measure of angle ACB?

Answer 1

@LastDayWork

Answer 2

What does that 100° below the circle imply ?

Answer 3

<ABC = 42°,
and,
< ADB = 100° , where, D is the Center,
SO,
<DBA = <DAB = (180-100) / 2 = 40°,
SO,
<BAC = 90+40 = 130°,
Hence,
<ACB = 180 -42 -130 = 180-172 = 8 this is related to inscribed angles

Answer 4

IDK how you inferred this line
"< ADB = 100° , where, D is the Center, "