Graph the exponential function f(x)=-(2/3) . To graph the function, plot the points on the graph with x-values -2,-1,0,1,and 2, draw all asymptotes.
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Sorry it should be: Graph the exponential function \[f(x)=-(\frac{ 2 }{ 3 })^{x} \] . To graph the function, plot the points on the graph with x-values -2,-1,0,1,and 2, draw all asymptotes.
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how do i plot this?
Make yourself a table of x and y values: x y -2 -(2/3)^-2 -1 -(2/3)^-1 0 -(2/3)^0 1 -(2/3)^1 2 -(2/3)^2 (you'll have to evaluate the expressions I wrote in the y column) Plot the points on your graph. Draw a smooth curve through them.
Don't be worried if your graph looks different than @ikram002p's graph: he graphed \[y = (\frac{2}{3})^x\]not\[y = -(\frac{2}{3})^x\]
so for the points I have: -2, -2.25, -1,-1.5, 0,-1,1,-0.67, 2,-0.44. is that right?
Yes, here they are in both symbolic and numeric form: \[\begin{array}{ccc} x & y & y\\\hline\\ -2 & -\frac{9}{4} & -2.25 \\ -1 & -\frac{3}{2} & -1.5 \\ 0 & -1 & -1. \\ 1 & -\frac{2}{3} & -0.666667 \\ 2 & -\frac{4}{9} & -0.444444 \\ \end{array}\]
oh , sry i dint note the -ve sighn, how ever im she not he :o
I wonder if your icon wasn't loading for me earlier today when I wrote that. It's not the sort of image that most guys would choose!
ya lol ! it would be weird if im he with this icon :o :P
Indeed. Well, again, my apologies!
np, its ok ^^
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