Question

Find 3 positive values for "c" so that the trinomial is factorable

11y^2-40y+c

Answer 1

11 is prime, right?

Answer 2

yes..

Answer 3

it is. that means that we're going to have something like \[(11x + a)(x - b)\]as our factoring.

Answer 4

now, we need to find a pair of factors \(f_1, f_2\) such that \(11*f_1 + f_2=-40\) and \(f_1*f_2 = c\)

Answer 5

one example would be -3 and -7. 11*-3 = -33, -33 + -7 = -40. -3*-7 = 21

\[(11y-7)(y-3) = 11y^2-33y-7y+21 = 11y^2-40y+21\]

Answer 6

Thank you whpalmer4