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find the zeros for each polynomial function and give the multiplicity for each zero f(x)= -3(x+1/2)(x-4)^3
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Do you know how to find the zeros here?
no do I solve for 0
a polynomial can be written as a product of factors \((x-r_1)(x-r_2)...(x-r_n)\) where \(r1...r_n\) are the roots or zeros. You have \[f(x) = -3(x+\frac{1}{2})(x-4)^3\]What do you think your zeros are going to be?
the zeros are the same values that make any of those product terms = 0 \[(x+\frac{1}{2}) = 0\]\[(x-4)=0\]
do you know what the multiplicity of a zero is?
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