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4^ 3x=6000 Helper gets a medal :) !
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Is that \[4^{3x} =6000\] or \[4^3x=6000\]
the first one
log4^3x=log6000 3xlog4=log6000 3x=log6000/log4 3x=6.275 x=2.092 approximately
That's one of three solutions...can you find the other two? :-)
i may be wrong but im pretty sure theres only 1 solution
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Yes, you're wrong. There are 3 solutions. Two of them are complex numbers.
.........in algebra 2 they usually only ask for the real number
Just because they aren't asking for them doesn't mean they don't exist, you know :-)
in the scope of algebra 2 you don't need to find them
Don't make the mistake of assuming your algebra 2 curriculum is the same as everyone else's! It ain't necessarily so...
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