john's pizza sold meatball cheese for $6 and cheese pizza for $5. 300 pizzas were sold for a total sale of $1,600. How many of each type of pizza did John sell? What was the dollar sale of each?

Question

whpalmer4 · Answer

let $m$ represent meatball cheese pizzas and $c$ represent cheese pizzas.

we know 300 pizzas were sold, so$$m+c=300$$we know meatball cheese pizzas sell for $6 each and cheese pizzas sell for $5 each, so revenue for $m$ meatball cheese pizzas and $c$ cheese pizzas would be $$6m+5c = 1600$$

Now we have two equations in two unknowns, which is sufficient to solve for both unknowns.  Do you know how to do that?

whpalmer4 · Answer

I would suggest solving the first equation for $c$, and substituting the right hand side into the second equation wherever you see $c$.  That will give you an equation in terms of $m$.  Solve that, and then use the value you found for $m$ along with the first equation to find the value of $c$.

Once you know how many pizzas of each type were sold, just multiply the number for each type by the price for that type to get the dollar volume for that type.

anonymous · Answer

Thank you so much for your help @whpalmer4! I kinda forgot how Algebra works because I'm focusing too much on Statistics and Probability.