Question

Medal and fan awarded !
Which of the following is not a way to represent the solution of the inequality 3(2x - 1) greater than or equal to 4(2x - 3) - 3?

Answer 1

x less than or greater to 6

6 greater than or equal to x

A number line with a closed circle on 6 and shading to the left

A number line with a closed circle on 6 and shading to the right

Answer 2

\(\rm\Large\color{green}{Is~this~how~it~looks?}\)
\[3(2x-1)\ge4(2x-3)-3\]

Answer 3

Yes

Answer 4

OK good so first you are going to distribute the 3 and the 4 and it will look like this
\[6x-3\ge8x-12-3\]

Then you combine like terms and get this
\[6x-3\ge8x-9\]
Do you know what to do from here?

Answer 5

Not really , this is a pre-test for stuff i have not learned yet . When i attempted to solve that i got 3 is greater than or equal to 3 , which is not an answer choice. But i have an idea of what the answer is ... C ? @tester97

Answer 6

i ment 3 is greater than or equal to x

Answer 7

Ok so what you would do is move the 9 to the left side and the 6x to the right. It would look like this \[6\ge2x\]
then you solve for x and get\[3 \ge x~ or~ x \le3\]
which is not an answer choice as you said, but using an educated guess i would also say C

Answer 8

Alright thanks for the help

Answer 9

\(\frak\Large\color{red}{No~problem~@Mcdonaldsistrash}\)

\(\Large\color{green}{\ddot\smile}\)